A GEOMETRIC INTERPRETATION OF EQUAL SUMS OF CUBES

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Issue:

Science

 

Written by:

Janet B

 

Date added:

February 23, 2015

 

Level:

University

 

Grade:

B

 

No of pages / words:

2 / 418

 

Was viewed:

3802 times

 

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Essay content:

We get the corner: We have . Let’s put our corner in the zero vector point: Then A=(0,0,0), D=(a,0,0), C=(0,b,0), B=(0,0,c). Similarly, The magnitude of cross product of two vector gives us the area of the parallelogram. So, the area of the triangle BCD is one half from the magnitude of cross product of vectors BD and BC...
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So, the area of the triangle BCD is one half from the magnitude of cross product of vectors BD and BC. Let p=Area of ?ABC r=Area of ?ACD q=Area of ?ABD s=Area of ?BCD Then we see that But we will try to find something looking like Let’s take an isosceles triangle ABC, where AB=AC=r, take a point D on BC and take BD=p, CD=q...
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