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Investigating The Rate Of Reaction Between Peroxydisulphate (Vi) Ions And Iodide Ions
Essay specific features
Written by:
Steve B
Date added:
November 4, 2016
Level:
Grade:
A
No of pages / words:
8 / 1964
Was viewed:
4698 times
Rating of current essay:
Essay content:
Finding the order for each reactant
4. Finding the rate-determining step.
5. Proposing a mechanism for the reaction.
6. Using Arrhenius' equation to find the activation enthalpy.
Background
The basic reaction for this can be illustrated with the following equation:
3I-(aq) + H2O2(aq) + 2H+(aq) > I3-(aq) + 2H2O(aq) (1)
The half equations for this reaction can be written as follows:
3I- ? I3- + 2e-
H2O2 + 2H+ + 2e- ? 2H2O
This reaction demonstrates that iodide ions are oxidised by hydrogen peroxide to tri-iodide ions...
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Thus, the iodine that is formed in reaction (1) is immediately transformed into iodide ion and we do not see the blue-black colour of the starch-iodide complex until all of the thiosulphate ion has reacted with I 2(aq) and is exhausted.
I3- (aq) + starch ? Starch-I5- complex + I-(aq)
Once the thiosulphate ion has been exhausted, the tri-iodide ion can react with the starch, forming the Starch-I5- complex, giving the blue-black colour...
displayed 300 characters
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